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Suppose you can afford to pay at most $2650 per month for a mortgage payment. If the maximum amortization period
you can get is 20 years, and you must pay 6% interest per year compounded annually, what is the most expensive
house you can buy? How much interest will you have paid to the lender at the end of the loan?
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This problem is tricky, since the payments are monthly, while compounding are annually.
So, the payments are desynchronized with compounding.
It means that monthly payments lie in the bank with no move and wait for the end of a year -
only then they are compounded, according to the problem.
Classic formulas for loan/mortgage are applicable for synchronized payments/compounding.
But we can modify the situation EQUIVALENTLY to get payments/compounding synchronized.
Indeed, we actually have annual payments of 12*2650 = 31800 dollars each, compounded annually.
Thus, it works as a classic loan for 20 years with annual payments of $31800
at the end of each year, compounded annually at the annual rate of 6%.
Now apply a standard loan formula
PMT =
where PMT is the annual payment ($31800); L is the loaned amount; r = 0.06 is the percentage rate
of rounding and n = 20 years. Then the formula becomes
31800 = .
From it, we get
L = = 364743.50.
It means that the most expensive house you can buy under given conditions is for $364,743.50. <<<---=== ANSWER
You will pay for the loan 20*12*2650 = 636000 dollars.
It means that interest you have paid to the lender for the loan is
636,000 - 364,743.50 = 271256.50 dollars. <<<---=== ANSWER
At this point, the problem is solved completely.
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The solution in the post by @Theo is inadequate to the problem.
It is because Theo introduces, considers and treats monthly compounding; but the bank does not perform
monthly compounding. According to the problem, the bank makes annual compounding, ONLY.
Theo introduces equivalent monthly rate; but it works as an equivalent scheme only under condition
when there are no intermediate compounding inside a year. When there are intermediate monthly compounding,
it immediately destroys equivalency.
Had the problem admit monthly compounding, the solution by @Theo would be correct.
But under the conditions, described in the post, @Theo' solution is inadequate.
It is why I called this problem "tricky".
It has a hidden underwater stone as a trap, and, therefore, should be treated carefully.