SOLUTION: The local theater group anticipates that it can sell about 450 adult tickets and 700 student tickets for an upcoming show. The price of adult tickets will be $3 more than the price
Question 1203891: The local theater group anticipates that it can sell about 450 adult tickets and 700 student tickets for an upcoming show. The price of adult tickets will be $3 more than the price of student tickets. How much should each ticket cost if they intend to take in $9,400 from ticket sales? Found 3 solutions by math_tutor2020, greenestamps, josgarithmetic:Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
Answer:
Students = $7
Adults = $10
Scratch work shown
x = price for students
x+3 = price for adults
700x = revenue from the students
450(x+3) = revenue from the adults
700x+450(x+3) = total revenue = 9400
700x+450(x+3) = 9400
Solving for x.
700x+450(x+3) = 9400
700x+450x+1350 = 9400
1150x+1350 = 9400
1150x = 9400-1350
1150x = 8050
x = 8050/1150
x = 7
x+3 = 7+3 = 10
The price for each student should be $7, while the price for each adult should be $10.
The 450 adult tickets, each costing $3 more than a student ticket, bring in an "additional" 450($3) = $1350.
So the total of $9400 can be thought of as 450+700 = 1150 tickets costing the same amount, plus the additional $1350. That means the 1150 tickets that each cost the same sell for a total of $9400-$1350 = $8050. The cost for each of them is then $8050/1150 = $7.
ANSWER: The student tickets should cost $7 each, the adult tickets $7+$3 = $10 each.
Solving the problem in exactly the same way using formal algebra looks like this:
x = cost of a student ticket
x+3 = cost of an adult ticket