SOLUTION: a theater group made appearances in two cities. The hotel charge before tax in the second city was $1000 lower than in the first. The tax in the first city was 10%, and the tax in

Question 1200644: a theater group made appearances in two cities. The hotel charge before tax in the second city was $1000 lower than in the first. The tax in the first city was 10%, and the tax in the second city was 6%. The total hotel tax paid for the two cities was $
420. How much was the hotel charge in each city before tax?
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
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a theater group made appearances in two cities.
The hotel charge before tax in the second city was $1000 lower than in the first.
The tax in the first city was 10%, and the tax in the second city was 6%.
The total hotel tax paid for the two cities was $420.
How much was the hotel charge in each city before tax?
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Let x be the hotel charge in the first city before tax, in dollars. Then that in the second city is (x-1000) dollars. Write the total hotel tax paid for the two cities 0.1x + 0.06(x-1000) = 420 dollars. Simplify and find x 0.1x + 0.06x - 60 = 420 0.16x = 420 + 60 = 480 x = 480/0.16 = 3000. ANSWER. $3000 in the first city and $2000 in the second city. CHECK. 0.1*3000 + 0.06*2000 = 300 + 120 = 420 dollars. ! correct !

Solved.

Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!

CITY BASE RATE TAX RATE TAX 1 c+1000 10% 0.1(c+1000) 2 c 6% 0.06c TOTAL 420

Understand what equation to create and solve....
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