SOLUTION: If x = (1 + y) (1 + y²) (1 + y³)... (1 + y^n) Find dx/dy (when y = 1)

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Question 1200001: If x = (1 + y) (1 + y²) (1 + y³)... (1 + y^n)
Find dx/dy (when y = 1)
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
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If x = (1 + y) (1 + y²) (1 + y³)... (1 + y^n)
Find dx/dy (when y = 1)
~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

Apply the formula for the derivative of a product.


You will get that the derivative dx/dy is the sum of n addends.


The k-th addend is

    .


At y= 1, the k-th addend is   = .


The sum of n these addends is   = .    ANSWER

Solved.



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