SOLUTION: a) A total of $40,000 was invested, part of it at 12% interest and the remainder at 15%. If the total yearly interest from both investments was $5,800. How much was investe

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Question 1188420: a) A total of $40,000 was invested, part of it at 12% interest and the remainder at 15%.
If the total yearly interest from both investments was $5,800. How much was invested at each rate
Answer by greenestamps(13198)   (Show Source): You can put this solution on YOUR website!


Bad data, requiring answers that are not whole numbers of dollars, and not even whole numbers of cents....

x = amount invested at 12%
40000-x = amount invested at 15%

The total interest was 5800:



You can do the algebra to try to find the answer.

Here is a quick informal way to find the answer.

All $40,000 invested at 12% would yield $4800 interest; all at 15% would yield $6000.
Look at the three numbers 4800, 5800, and 6000 on a number line and observe/calculate that 5800 is 1000/1200 = 5/6 of the way from 4800 to 6000.
That means 5/6 of the total was invested at the higher rate.

5/6 of $40,000 is not a whole number....
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