SOLUTION: A chemist has three different acid solutions. The first acid solution contains 20% acid the second it contains 30% and the third contains 75%. They want to use all three solutions

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Question 1180814: A chemist has three different acid solutions. The first acid solution contains 20% acid the second it contains 30% and the third contains 75%. They want to use all three solutions to obtain a mixture of 96 L containing 45% acid using two times as much of the 75% solution as the 30% solution. How many liters of each solution should be used.
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
CONC %        VOLUME       PURE
  20          96-3v       0.2(96-3v)
  30           v          0.3v
  75           2v        0.75*2v
-----------------------------------
  45          96 L         43.2

You can see what equation to make from this.

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