SOLUTION: Solve. An investment is worth $3031 in 1994. By 1998 it has grown to $3759. Let y be the value of the investment in the year x, where x = 0 represents 1994. Write a linear equat

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Question 1176775: Solve.
An investment is worth $3031 in 1994. By 1998 it has grown to $3759. Let y be the value of the investment in the year x, where x = 0 represents 1994. Write a linear equation that models the value of the investment in the year x.
Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi
 x = 0 represents 1994  (0, 3031)
and
  (3759-3031)/3 = 728/3 = 242.67
Let x be  the investment in the year x.
 y = $3031 + $242.67x

 3031 + 3*($242.67) = $3759 checks
Wish You the Best in your Studies.


Answer by ikleyn(52855)   (Show Source): You can put this solution on YOUR website!
.
An investment is worth $3031 in 1994. By 1998 it has grown to $3759. Let y be the value of the investment
in the year x, where x = 0 represents 1994. Write a linear equation that models the value of the investment in the year x.
~~~~~~~~~~~~ 


If  $3031 represents the investment amount in 1994 

and $3759 represents the investment amount in 1998, 4 years later,


then the rate of linear growth is   = 182 dollars per year.


Then the linear equation you request for is


    y = 3031 + 182x.                        ANSWER

Solved.


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