SOLUTION: A Broadway theater has 600 ​seats, divided into​ orchestra, main, and balcony seating. Orchestra seats sell for $60 main seats for $50 and balcony seats for $30. If all the se

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: A Broadway theater has 600 ​seats, divided into​ orchestra, main, and balcony seating. Orchestra seats sell for $60 main seats for $50 and balcony seats for $30. If all the se      Log On

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Question 1175570: A Broadway theater has 600 ​seats, divided into​ orchestra, main, and balcony seating. Orchestra seats sell for $60 main seats for $50 and balcony seats for $30. If all the seats are​ sold, the gross revenue to the theater is $27,000  If all the main and balcony seats are​ sold, but only half the orchestra seats are​ sold, the gross revenue is $23,400 How many are there of each kind of​ seat?

Answer by ikleyn(52752) About Me  (Show Source):
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A Broadway theater has 600 ​seats, divided into​ orchestra, main, and balcony seating.
Orchestra seats sell for $60 main seats for $50 and balcony seats for $30.
If all the seats are​ sold, the gross revenue to the theater is $27,000  
If all the main and balcony seats are​ sold, but only half the orchestra seats are​ sold, the gross revenue is $23,400
How many are there of each kind of​ seat?
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From the condition, half the orchestra seats cost  27000 - 23400 = 3600  dollars.

Thus the half the number of orchestra seats is  3600%2F60 = 60,  
and full number of orchestra seats is 2*60 = 120.


Part of the problem is just solved.


For the other part, we have 

    - the cost of main and balcony seats total of 23400-3600 = 19800 dollars, and 

    - the total of these two types of seats is  600-120 = 480.


Let x be the number of main seats;  then the number of the balcony seats is  (480-x).



Then we write the money equation for these two types of seats

    50*x + 30*(480-x) = 19800  dollars.


From this equation  x = %2819800-30%2A480%29%2F%2850-30%29 = 270.


ANSWER.  120 orchestra seats;  270 main seats and the rest  600-120-270 = 210 seats.

Solved.