SOLUTION: The admission fee at an amusement park is $2.00 for children and $5.20 for adults. On a certain day, 237 people entered the park, and the admission fees collected totaled $810. How

Question 1164803: The admission fee at an amusement park is $2.00 for children and $5.20 for adults. On a certain day, 237 people entered the park, and the admission fees collected totaled $810. How many children and how many adults were admitted?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39615)   (Show Source): You can put this solution on YOUR website!
That description, if x is for children count and y for adult count,

Solve in any way you need or want.
Answer by ikleyn(52766)   (Show Source): You can put this solution on YOUR website!
.

Let x be the number of adults; then the number of children is (237-x). The money equation (the revenue equation) is 5.20*x + 2*(237-x) = 810 dollars. From the equation x = = 105. ANSWER. 105 adults and the rest, 237-105 = 132, are children. CHECK. 5.20*105 + 132*2.00 = 810 dollars. ! Correct !

Solved.

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It is a standard and typical tickets problem.

There are different methods of solving such problems.
In this site, there are lessons
    - Using systems of equations to solve problems on tickets
    - Three methods for solving standard (typical) problems on tickets
explaining and showing all basic methods of solving such problems.

From these lessons, learn on how to solve such problems once and for all.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Systems of two linear equations in two unknowns".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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