SOLUTION: Two cars start from towns 540 mi apart and travel toward each other. They meet after 6 hr. Find the speed of each car if one travels 10 mph faster than the other.

Question 1135801: Two cars start from towns 540 mi apart and travel toward each other. They meet after 6 hr. Find the speed of each car if one travels 10 mph faster than the other.

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!

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Answer by ikleyn(52834)   (Show Source): You can put this solution on YOUR website!
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            Ignore post by @josgarithmetic, since it is totally wrong (giving the answer of 45 mph for the slower car).

            The correct solution is below:

Let "r" be the speed of the slower car. Then 6r + 6*(r+10) = 540 <<<---=== the sum of the two distances 6r + 6r + 60 = 540 12r = 540-60 r = 480/12 = 40. ANSWER. The slower car speed is 40 mph; the faster car speed is 50 mph.

Solved.

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