SOLUTION: Bob is saving money that he earns at his part time job. He deposits $100 at the end of each month into a saving account that pays interest at 3% , compounded monthly. Bob would lik

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Question 1133060: Bob is saving money that he earns at his part time job. He deposits $100 at the end of each month into a saving account that pays interest at 3% , compounded monthly. Bob would like to know what his savings will be in the end of 1 year.

Found 2 solutions by Olasko, ikleyn:
Answer by Olasko(10)   (Show Source): You can put this solution on YOUR website!
Using: A = P + PRT/100
A = $100 + $100 * 5 /100
A = $100 + $5
He will have $105 at the end of 1year

Answer by ikleyn(52769)   (Show Source): You can put this solution on YOUR website!
.
Bob is saving money that he earns at his part time job. He deposits $100 at the end of each month into a saving account
that pays interest at 3% , compounded monthly. Bob would like to know what his savings will be in the end of 1 year.
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            Pay attention on how I edited your post to make it precisely correct.


It is a classic Ordinary Annuity saving plan. The general formula is 


    FV = ,    (1)


where  FV is the future value of the account;  P is the monthly payment (deposit); r is the monthly percentage yield presented as a decimal; 
n is the number of deposits (= the number of years multiplied by 12, in this case).


Under the given conditions, P = 100;  r = 0.03/12;  n = 12*1 = 12.  So, according to the formula (1), you get at the end of the 1-th year


    FV =  =  = $1216.64.


Note that you deposit only  12*1*$100 = $1200.  The rest is what the account earns/accumulates in 1 year.

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On Ordinary Annuity saving plans,  see the lessons
    - Ordinary Annuity saving plans and geometric progressions
    - Solved problems on Ordinary Annuity saving plans
in this site.

The lessons contain  EVERYTHING  you need to know about this subject,  in clear and compact form.

When you learn from these lessons,  you will be able to do similar calculations in semi-automatic mode.


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