SOLUTION: Mr Horla bought 8plates and 12 drinking cups from a shop. A plate cost him 5cents more than a drinking cup if he spent 9 dollars and 40 cents on all cups and plates together, how

Question 1124505: Mr Horla bought 8plates and 12 drinking cups from a shop.
A plate cost him 5cents more than a drinking cup if he spent 9 dollars and 40 cents on all cups and plates together, how much did he pay for a plate and a drinking cup.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
he bought 8 plates and 12 drinking cups.

1 plate costs 5 cents more than 1 drinking cups.

if the price of the drinking cup is x, then the price of the plate is x + .05.

the total paid is 9 dollars and 40 cents = 9.4.

your equation is 12 * x + 8 * (x + .05) = 9.4

simplify this to get 12 * x + 8 * x + 8 * .05 = 9.4

combine like terms and simplify further to get 20 * x + .4 = 9.4

subtract .4 from both sides of the equation to get 20 * x = 9

solve for x to get x = 9 / 20 = .45

x is the price of a cup = .45
x + .05 is the price of a plate = .5

confirm this is true by substituting in the original equaiton to get:

12 * x + 8 * (x + .05) = 9.40 becomes 12 * .45 + 8 * .5 = 9.40 which becomes 5.4 + 4 = 9.4 which becomes 9.4 = 9.4 which is true, confirming the solution is correct.

the solution is that each cup costs 45 cents and each plate costs 50 cents.

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