SOLUTION: Susan invests 2 times as much money at 11% than she does at 9%. If her total interest after 1year is $930, how much does she have invested at each rate?

Question 1124232: Susan invests 2 times as much money at 11% than she does at
9%. If her total interest after 1year is $930, how much does she have invested at each rate?
Answer by ikleyn(52903) (Show Source): You can put this solution on YOUR website!
.

0.09*x + 0.11*(2x) = 930


0.09x + 0.22x = 930.


0.31x = 930


x =  = 3000.


Answer.   $3000 invested at 9%  and  $6000 invested at 11%.


Check.    0.09*3000 + 0.11*6000 = 930  dollars.   ! Correct !

Solved.

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