SOLUTION: Part of $6,000 is invested at 12%, another part at 14%, and the remainder at 15% yearly interest. The total yearly income from the three investments is $840. The sum of the amounts

Question 1118391: Part of $6,000 is invested at 12%, another part at 14%, and the remainder at 15% yearly interest. The total yearly income from the three investments is $840. The sum of the amounts invested at 12% and 14% equals the amount invested at 15%. How much is invested at each rate?

Found 2 solutions by greenestamps, josgarithmetic:
Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!

"The sum of the amounts invested at 12% and 14% equals the amount invested at 15%."

That means half of the $6000 was invested at 15%
15% of $3000 is $450, so the amount of interest from the other two investments is $840-$450 = $390.

If all of the remaining $3000 were invested at 12%, the interest would be $360; if all were invested at 14%, the interest would be $420.

The actual remaining amount of interest, $390, is exactly halfway between $360 and $420; that means the amounts invested at 12% and 14% are equal -- $1500 in each.

Answer: $3000 at 15%; $1500 at 14%; $1500 at 12%.

CHECK: .15(3000)+.14(1500)+.12(1500) = 450+210+180 = 840
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!

x at 12% y at 14% x+y at 15% ------------------ ------------------2x+2y=6000 or x+y=3000

Yearly Income, $840
, and .

------from hear, the algebra is a few short simple steps....
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