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You are given a "universal" set A of 75 cars, and two subsets A of 10 cars and B of 18 cars.
You also are given that the complement to the union of the sets A and B has 53 elements; hence, the union of A and B has 75 - 53 = 22 elements.
Thus we know that n(AUB) = 23 (the number of elements in the union), and n(A) = 10, n(B) = 18.
Then the number of elements in the intersection n(AnB) = n(A) + n(B) - n(AUB) = 10 + 18 - 23 = 5.
Answer. 5 cars needed both brake and exhaust system repairs.
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To get more acquaintance with this circle of problems, look into the lesson
- Counting elements in sub-sets of a given finite set
in this site.