SOLUTION: Cindy invested $24,000 for one year, part at 6% and part at 9%. If the total amount of interest she earned was $1,740, how much money did he invest at each rate?
Algebra.Com
Question 1115137: Cindy invested $24,000 for one year, part at 6% and part at 9%. If the total amount of interest she earned was $1,740, how much money did he invest at each rate?
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
0.06x + 0.09(24,000-x) = 1,740
0.06x + 2160 - 0.09x = 1740
-0.03x = -420
x = 14,000
She invested 14,000 at 6% and 10,000 at 9%
----------------------------------------------------
Check:
14,000*0.06 = 840
10,000*0.09 = 900
. . . . . . .-----
Total . . . $1,740 Correct
RELATED QUESTIONS
.need equation so I can solve the problem
math problem
?Arlene invested $29,000 for... (answered by ReadingBoosters)
Ethan invested $19,000 for 1 year, part at 11% simple interest and part at 13% simple... (answered by ikleyn,mananth,Edwin McCravy,greenestamps)
invested 10000$ for 1 year party at 7% and part 6.25% if she earned a total interest of... (answered by mananth)
Tracy invested $38000 for one year, part at 11% interest and part at 9% interest. If she... (answered by solver91311)
the total interest earned after one year Php 100 000 is invested, part of 6% annual... (answered by ikleyn)
the total interest earned after one year Php 100 000 is invested, part of 6% annual... (answered by greenestamps)
George invested $19,000 for one year, part at 11% and part at 12%. If the total amount... (answered by ikleyn)
Marissa invested $7000 for 1 year. Part was invested at 4% simple interest and part... (answered by checkley79)
You invested $7000 in two accounts paying 7% and 6% annual interest, respectively. If... (answered by mananth)