SOLUTION: a woman has a total of 9,000 to invest.she invest part of the money in an account that pays 8% per year and the rest in an account that pays 9%per year if the interest earned in th

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Question 1109966: a woman has a total of 9,000 to invest.she invest part of the money in an account that pays 8% per year and the rest in an account that pays 9%per year if the interest earned in the first year is 750 how much did she invest in each account
Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
interest + interest      = total interest


0.08*x   + 0.09*(9000-x) = 750    dollars


0.08x + 810 - 0.09x = 750

-0.01x = 750 - 810 = -60  ====>  x =  = 6000.


Answer.  $6000 was invested at 8%.  The rest   9000-6000 = 3000 dollars were invested at 9%.


Check.   0.08*6000 + 0.09*3000 = 480 + 270 = 750 dollars.   ! Correct !

Solved.

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To see many other similar solved problems on investment,  look into the lesson
    - Using systems of equations to solve problems on investment
in this site.

You will find there different approaches  (using one equation or a system of two equations in two unknowns),  as well as
different methods of solution to the equations  (Substitution,  Elimination).

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Systems of two linear equations in two unknowns".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


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