SOLUTION: If Joshua paid for 48,000$ for all of his expenses, consiting of dresses and shoes, with each dress being 400$ and each pair of shoes being 1000$, after he sold all of then he had
Algebra.Com
Question 1108917: If Joshua paid for 48,000$ for all of his expenses, consiting of dresses and shoes, with each dress being 400$ and each pair of shoes being 1000$, after he sold all of then he had a profit of 18,000$ with a profit of 20% for the dresses, and profit of 50% for the shoes, how many shoes and dresses did Joshua buy?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
let x = number of dresses and y = number of shoes.
the cost of each dress is 400 dollars and the cost of each pair of shoes is 1000 dollars.
the total cost is 48,000.
therefore:
400x + 1000y = 48,000.
that equation says that the number of dresses * 400 plus the number of pairs of shoes * 1000 equals the total cost of 48000.
the total profit is 18000.
the profit margin on dresses is 20%.
the profit margin on shoes is 50%.
the profit on the dresses is 20% of the cost of the dresses.
therefore, the profit on the dresses is .20 * 400 * x.
the profit on the shoes is 50% of the cost of the shoes.
therefore, the profit on the shoes is .50 * 1000 * y.
since the total profit is 18,000, you get:
.20 * 400 * x + .50 * 1000 * y = 18,000.
looks like we have 2 equations that need to be solved simultaneously.
they are:
400x + 1000y = 48,000
.20 * 400 * x + .50 * 1000 * y = 18,000
simplify the second equation and leave the first equation as is to get:
400x + 1000y = 48,000
80x + 500y = 18,000
leave the first equation as is and multiply both sides of the second equation by 2 to get:
400x + 1000y = 48,000
160x + 1000y = 36,000
subtract the second equation from the first to get:
240x = 12,000
solve for x to get:
x = 12000 / 240 = 50
you have x = 50
your 2 original equations, after simplification, are:
400x + 1000y = 48,000
80x + 500y = 18,000
replace x with 50 in the first original equation to get:
400*50 + 1000y = 48,000
simplify to get:
20,000 + 1000y = 48,000
solve for y to get y = (48,000 - 20,000) / 1000 = 28.
you have x = 50 and y = 28
replace x with 50 and y with 28 in the second original equation to get:
80x + 500y = 18,000 becomes:
80 * 50 + 500 * 28 = 18,000
simplify to get 4,000 + 14,000 = 18,000.
both original equations are true when x = 50 and y = 28, so that must be your solution.
she bought 50 dresses and 28 pairs of shoes.
the dresses cost her 50 * 400 = 20,000.
the shoes cost her 28 * 1000 = 28,000.
her total cost was 20,000 + 28,000 = 48,000.
she made 20% profit on the dresses.
she made 50% profit on the shows.
her profit on the dresses was .20 * 20,000 = 4,000.
her profit on the shoes was .50 * 28,000 = 14,000.
her total profit was 4,000 + 14,000 = 18,000.
solution checks out and is therefore assumed to be good.
solution is 50 dresses and 28 pairs of shoes were bought.
RELATED QUESTIONS
Hi
Mary bought some shoes and dresses for $296.00. The dress cost $24 the shoes $20 .... (answered by josgarithmetic,greenestamps)
I need help in aiding my daughter with working the following word problem: A fatory... (answered by scott8148)
Jane has a dress shop. She has space for 200 dresses. She sells only red and blue... (answered by ankor@dixie-net.com)
Jane has a dress shop. She has space for 200 dresses. She sells only red and blue... (answered by ptaylor)
each dress in a store was marked $3.00 off the original price. a woman paid $46.00 for 2... (answered by ikleyn)
please help me with the equation: Three partners, James, Jacob and Joshua, have an... (answered by greenestamps)
Hello!
Can anyone help please?
My question is:
A woman has four dresses for... (answered by psbhowmick)
Barbara bought a pair of dress shoes and a pair of sports shoes. The combined cost was... (answered by checkley77)
Dorca earns $12.00 for each dress she produces. Each of Dorca's dresses sells for $50. If (answered by swiemers)