SOLUTION: Susan invests 3 times as much money at 11% as she does at 7%. If her total interest after 1 year is $2400, how much does she have invested at each rate?

Algebra.Com
Question 1102815: Susan invests
3 times as much money at
11% as she does at
7%. If her total interest after
1 year is
$2400, how much does she have invested at each rate?

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


Let x be the amount invested at 7%; then the amount invested at 11% is 3x.

The interest from the first investment is then .07 times x; the interest from the second is .11 times 3x.

Since the total interest is $2400,





She invested x = $6000 at 7% and 3x = $18000 at 11%.

CHECK:

RELATED QUESTIONS

Susan invests 3 times as much money at 11% as she does at 8%. If her total interest after (answered by richwmiller)
Susan invests 3 times as much money at 11% as she does at 7%. If her total interest after (answered by ikleyn)
Susan invests 2 2 times as much money at 11 11% as she does at 7%. If her... (answered by jorel555)
Susan invests 3 times as much money at 11% as she does at 9%. If her total interest after (answered by richwmiller)
Susan invests 2 times as much money at 12% as she does at 9%. If her total interest after (answered by addingup,josmiceli)
Susan invests 3 times as much money at 5% as she does at 4% . If her total interest... (answered by ewatrrr)
Susan invests 2 times as much money at 5% as she does at 4%. If her total interest after... (answered by ReadingBoosters)
Hi I need help on this word problem. Susan invests 2 times as much money at 10% as... (answered by ikleyn,josgarithmetic)
Susan invests 2 times as much money at 11% than she does at 9%. If her total interest... (answered by ikleyn)