SOLUTION: I subscribe to the Comic-of-the-Month Club. Each month I can buy any number of the 48 titles offered by the club. The first month I bought five comics for $19.07. The s
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Question 1098463: I subscribe to the Comic-of-the-Month Club. Each month I can buy any number of the 48 titles offered by the club. The first month I bought five comics for $19.07. The second month I bought two comics for $8.72. The next month I bought six of the club offerings for $22.52. In May I bought three more for $12.17. The club charges a fee for each comic and a handling fee for the entire order. How much would it have cost to buy all 48 titles at the same time
Found 2 solutions by josmiceli, richwmiller:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the price of 1 comic
Let = the fee for 1 comic
Let = the handling fee/order
-----------------------------------
1st month:
(1)
2nd month:
(2)
3rd month:
(3)
May order:
(4)
-----------------------------
Multiply both sides of (2) by
and subtract (3) from (2)
(2)
(3)
---------------------------------
-----------------
(1)
(1)
and
(2)
(2)
------------------------------
Multiply both sides of (2) by
and subtract (2) from (1)
(1)
(2)
------------------------------
---------------------------
For all 48 titles ordered at the same time:
$167.42 for the order
------------------------
check:
(4)
(4)
(4)
(4)
OK
You can check (1), (2), (3)
---------------------------
Note that there is no way to separate
and to find what they are,
but you don't have to to solve the problem.
Feel free to get another opinion and
check my math
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
5c+h=19.07
2c+h=8.72
6c+h=22.52
3c+h=12.17
6c+2h=24.34
6c+h=22.52
h=24.34-22.52
h=1.82
check
5c+1.82=19.07
5c=19.07-1.82=17.25
c=17.25/5
c=3.45
2c+h=8.72
2*3.45+1.82=8.72
6c+h=22.52
6*3.45+1.82=22.52
3c+h=12.17
3*3.45+1.82=12.17
ok
48c+1.82
48*3.45+1.82=$167.42 to buy all 48 at once
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