SOLUTION: 72(n+6)-80(n)=200 Find N and what is 72n times n?

Question 109529: 72(n+6)-80(n)=200

Find N and what is 72n times n?
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Find N?
I presume you mean Find n, because I don't see any N:
72(n+6)-80(n) = 200 Simplify the left side.
72n+432-80n = 200
-8n+432 = 200 Subtract 432 from both sides.
-8n = -232 Divide both sides by -8.
n = 29
Substitue n = 29
=

RELATED QUESTIONS
what is the average of n,n+2,n+6 and n+8 ? (answered by josgarithmetic)

N^6 times N^2 (answered by colliefan)

If n(A)=10,n(A u B) =28 and n(A n B)=6; what is... (answered by Edwin McCravy)

What is the value of n in this equation? 45 - 5 + 80 + n =... (answered by vidhyak)

if n = -5, what numbers do n, n + 2, n + 4, and n + 6... (answered by richard1234)

6/7 = 13/n what is n... (answered by venugopalramana)

The mean of the list n, n + 3, n+4, n+5, n+6, n+8, n+10, n + 12, n+15 is 11. What is... (answered by MathLover1,josgarithmetic)

n-20=8-n what is... (answered by richwmiller)

What is 6 times the difference of n and 6? (answered by checkley79)