SOLUTION: A man has invested $18,000 in two parts. One part is invested at 8% and the remainder at 10%. The income from the 10% investment is $360 more than the income from the 8% investment

SOLUTION: A man has invested $18,000 in two parts. One part is invested at 8% and the remainder at 10%. The income from the 10% investment is $360 more than the income from the 8% investment

Algebra.Com

Question 1094642: A man has invested $18,000 in two parts. One part is invested at 8% and the remainder at 10%. The income from the 10% investment is $360 more than the income from the 8% investment. How much does he invest at each rate?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
a+b=18000
.10a=.08b+360
RELATED QUESTIONS
A man has $215,000 invested in three properties. One earns 12%, one 10% and one 8%. His... (answered by richwmiller)

A man has $295,000 invested in three properties. One earns 12%, one 10% and one 8%. His... (answered by ikleyn)

A man has $250,000 invested in three properties. One earns 12%, one 10% and one 8%. His... (answered by mananth,MathTherapy)

A man has invested $8000, part of 10% and the remainder at 6% simple interest. how much... (answered by mananth)

a sum of 20000 is invested, part at 10% and the remainder at 8%, find the amount invested (answered by mananth)

A man invested part of $15,000 at 12% and the remainder at 8%. If his annual income from (answered by mananth,MathTherapy,greenestamps)

Part of a $8, 000 inheritance was invested at 10% interest and the rest was in- vested at (answered by stanbon)

Sally invested $3000 in two parts. One part was invested at 8% interest and the second... (answered by bucky)

A person invested $6,700 for one year, part at 8%, part at 10% and the remainder at 12%. (answered by stanbon)