SOLUTION: How many liters of a 90​% acid solution must be mixed with a 30​% acid solution to get 540 L of a 80​% acid​ solution?
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Question 1087057: How many liters of a 90% acid solution must be mixed with a 30% acid solution to get 540 L of a 80% acid solution?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let n and 540-n be the amounts of 90% acid and 30% acid, respectively. Then
.9n+.3(540-n)=.8(540)=432
Solve for n
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