SOLUTION: In 2008​, funding for a program increased by .80 billion dollars from the funding in 2007. In 2009​, the increase was .37 billion dollars over the funding in 2008. For
Algebra.Com
Question 1079861: In 2008, funding for a program increased by .80 billion dollars from the funding in 2007. In 2009, the increase was .37 billion dollars over the funding in 2008. For those three years the funding was 10.43 billion dollars. How much was funded in each of these three years?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let n be the amount funded in 2007. Then 2008 would be n+.8, and 2009 would be n+.8+.37, or n+1.17. So:
n+n+.8+n+1.17=10.43
3n=8.46
n=2.82
The funding for 2007 was 2.82 billion; for 2008 it was 3.62 bil, and for 2009 it was 3.99 bil. ☺☺☺☺
RELATED QUESTIONS
In 1995, funding for a program increased by 0.75 billion dollars from the funding... (answered by Theo)
In 1994, funding for a program increased by 0.19 billion dollars from the funding... (answered by Boreal)
In 1994, funding for a program increased by 0.28 billion dollars from the funding in... (answered by Boreal)
In 1991, funding for a program increased by 1.06 billion dollars from funding in 1990. In (answered by nyc_function)
Suppose that 20% of the college seniors support an increase in federal funding for care... (answered by ikleyn)
A community theater group finds that their funding is cut by 12% each year. This year,... (answered by Fombitz)
In some country the budget for defense exceeded the budget for education by $622.7 (answered by ikleyn)
In some country the budget for defense exceeded the budget for education by $622.7 (answered by ikleyn)
In 2009, the federal minimum wage in the United States increased from $6.55 per hour (in... (answered by josgarithmetic)