# SOLUTION: Stan invested \$17,000, part at 18% and part at 4%. If the total interest at the end of the year is \$1,380, how much did he invest at each rate?

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Stan invested \$17,000, part at 18% and part at 4%. If the total interest at the end of the year is \$1,380, how much did he invest at each rate?       Log On

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 Click here to see ALL problems on Money Word Problems Question 107855: Stan invested \$17,000, part at 18% and part at 4%. If the total interest at the end of the year is \$1,380, how much did he invest at each rate? Found 2 solutions by checkley71, scott8148:Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!.18X+.04(17,000-X)=1,380 .18X+680-.04X=1,380 .14X=1,380-680 .14X=700 X=700/.14 X=5,000 INVESTED @ 18% 17,000-5,000=12,000 INVESTED @ 4%. PROOF .18*5,000 +.04*12,000=1,380 900+480=1,380 1,380=1,380 Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!let x="part @ 18%", so 17000-x="part @ 4%" ... (18%)(x)+(4%)(17000-x)=1380 .18x+680-.04x=1380 ... .14x=700