SOLUTION: you buy computer for$ 150. the computers value decreased by 12.5 % each year. write an exponential function for the value of the computer ? to the nearst tenth of a year when the

Question 1077601: you buy computer for$ 150. the computers value decreased by 12.5 % each year.
write an exponential function for the value of the computer ?
to the nearst tenth of a year when the computer be worth $600?
to the nearst con, how much will the computer be worth in 10 years?
Answer by themasterofcircuits(27) (Show Source): You can put this solution on YOUR website!
V=V_0*e^(-k*t)
Where V_0 is the initial value of the computer, k is the depreciation constant, and t is the number of years.
In this case, V_0 is $150 and k is 12.5% or 0.125
so [V=150*exp(-0.125*t)]
The max value of V is $150, so the computer will only go down in price as the years go down, so the value of the computer will [NEVER] reach $600.
In 10 years: V(10)=150*exp(-0.125*10)= [$42.97]
RELATED QUESTIONS
you buy a computer for $1250 and its value decreases $150 per year. write an equation... (answered by rapaljer)

The value of a computer used in a business can be depreciated at a rate of 30% each year. (answered by mila nedic,ewatrrr,ikleyn)

Randolf bought a high-end computer system for $4800. The system depreciates at the rate... (answered by stanbon)

The value of a new computer network for an office is $12 000. If the depreciation of the... (answered by addingup)

write an exponential growth model that describes the situation. 58) you purchase an... (answered by Mathtut)

a computer is purchased for $3200.00. Its value each year is about 79% of the value the... (answered by checkley71,josmiceli)

A computer is purchased for $3200. Its value each year is about 79% of the value the... (answered by rfer)

A computer is purchased for $3200. Its value each year is about 79% of the value the... (answered by stanbon,rfer,Edwin McCravy)

The original value of a painting is $9,000 and the value increases by %7 each year. Write (answered by solver91311,stanbon)