SOLUTION: A man buys a lamp and a table for 390 $. The table cost 80 $ more than the lamp. Find the cost of each aricle.

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Question 107455: A man buys a lamp and a table for 390 $. The table cost 80 $ more than the lamp. Find the cost of each aricle.
Found 3 solutions by Dan3322, Annabelle1, MathLover1:
Answer by Dan3322(1)   (Show Source): You can put this solution on YOUR website!
A man buys a lamp and a table for 390 $. The table cost 80 $ more than the lamp. Find the cost of each aricle.
Answer by Annabelle1(69)   (Show Source): You can put this solution on YOUR website!
let the cost of the lamp be x
the cost of the table is then x+80
the total cost is then x+x+80
=2x+80
this is equal to 390
2x+80=390
Solved by pluggable solver: SOLVE a linear equation
Solve . Move 80 to the right: . Divide by 2:


so the lamp(x) was $155
the table then 155+80=235

Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
given:
A man buys a and a for $.
The cost $ more than the .
Find of each aricle.
then:

since
we will substitute it





............the cost of the lamp
then

..............the cost of the table
check:



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