SOLUTION: A manufacturer of telephones determines that the profit from producing and selling x telephones is P(x) = -.01x 2 + 6x – 500 dollars. a. How many telephones should be produced to m
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Question 1056798: A manufacturer of telephones determines that the profit from producing and selling x telephones is P(x) = -.01x 2 + 6x – 500 dollars. a. How many telephones should be produced to maximize the profit? b. What is the maximum profit? (This is an application of derivatives)
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
There is a formula for finding the peak when
the equation looks like
, it is:
----------------------------
You can also find the derivative of
and set it to zero to find the peak.
The derivative of is:
---------------------
Selling 300 telephones maximizes profit
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