SOLUTION: A person invested $5,200, part in bonds bearing 5.9% interest and the remainder in bonds bearing 7.6% interest. Both investments paid the same amount. How much, to the nearest doll

Question 1056635: A person invested $5,200, part in bonds bearing 5.9% interest and the remainder in bonds bearing 7.6% interest. Both investments paid the same amount. How much, to the nearest dollar, was invested in each?
Found 2 solutions by jorel555, MathTherapy:
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let n be the amount invested at 7.6%. Then:
.076n=.059(5200-n)
.017n=306.8
n=1804.70
$1804.70 was invested at 7.6%; $3395.30 was invested at 5.9%. ☺☺☺☺
Answer by MathTherapy(10557) (Show Source): You can put this solution on YOUR website!

A person invested $5,200, part in bonds bearing 5.9% interest and the remainder in bonds bearing 7.6% interest. Both investments paid the same amount. How much, to the nearest dollar, was invested in each?

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