SOLUTION: Joseph invests $5100 in two different accounts. The first account paid 9 %, the second account paid 3 % in interest. At the end of the first year he had earned $243 in interest. Ho

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Question 1050370: Joseph invests $5100 in two different accounts. The first account paid 9 %, the second account paid 3 % in interest. At the end of the first year he had earned $243 in interest. How much was in each account?
Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
0.09x+(5100-x)*0.03=243
9x+(15300-3x)=24300
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=1500.
  • Graphical form: Equation was fully solved.
  • Text form: 9x+15300-3x=24300 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( 9x+15300-3x=24300 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Moved 15300 to the right of expression
It becomes .
Look at .
Eliminated similar terms highlight_red%28+9%2Ax+%29,highlight_red%28+-3%2Ax+%29 replacing them with highlight_green%28+%289-3%29%2Ax+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Remove unneeded parentheses around factor highlight_red%28+6+%29
It becomes .
Look at .
Moved these terms to the left highlight_green%28+-24300+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Removed extra sign in front of -9000
It becomes .
Look at .
Solved linear equation highlight_red%28+6%2Ax-9000=0+%29 equivalent to 6*x-9000 =0
It becomes .
Result:
This is an equation! Solutions: x=1500.

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