SOLUTION: $20,000 is invested, part at 4% and remainder at 6%. The total income is $1050 from the 2 investments. Determine amt. at each rate. My attempt: Let x = amt. at 4% (4% is .

Algebra.Com
Question 1047034: $20,000 is invested, part at 4% and remainder at 6%. The total income is $1050 from the 2 investments. Determine amt. at each rate.
My attempt:
Let x = amt. at 4% (4% is .04)
20,000 - x = amt. at 6% (6% is .06)
Not sure from here. Thanks.

Found 2 solutions by Boreal, josmiceli:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
That's fine as far as you have gone.
make the two add to equal $1050.
.04x+.06(20000-x)=$1050
.04x+1200-.06x=1050
-,02x=-150
x=$7500 @4% ($300 a year)
20000-x=$12500@6%=$750 a year. They add to $1050

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
= amount invested @ 4%
= amount invested @ 6%





and


------------------------
$7,500 is invested @ 4%
$12,500 is invested @ 6%

RELATED QUESTIONS

marsha invested part of 18,000.00 at 16% and the remainder at 20%. Her total income from... (answered by rfer)
A part of P10,000 is invested at 4% and the remainder at 3. ½%. The annual income from (answered by Theo)
A part of P10,000 is invested at 4% and the remainder at 3. ½%. The annual income from (answered by Boreal,greenestamps)
Bianca has $4000 invested, part at 5% per annum and the remainder at 3% per annum simple... (answered by harpazo)
A couple invested part of P2,100,000 at 4% and the remainder at 7%. Their annual income... (answered by mananth)
Linda invests $25,000 for one year. Part is invested at 5%, another part at 6%, and the... (answered by ikleyn,greenestamps)
Solve the problem. Linda invests $25,000 for one year. Part is invested at 5%, another (answered by mananth)
part of $3000 is invested at 12% another part at 13% and the remainder at 14% yearly... (answered by jorel1380)
Part of $6,000 is invested at 12%, another part at 14%, and the remainder at 15% yearly... (answered by greenestamps,josgarithmetic)