SOLUTION: How many quarts of pure antifreeze must be added to 5 quarts of a 10​% antifreeze solution to obtain a 40​% antifreeze​ solution?

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Question 1044620: How many quarts of pure antifreeze must be added to 5 quarts of a 10​% antifreeze solution to obtain a 40​% antifreeze​ solution?
Found 3 solutions by addingup, ikleyn, Edwin McCravy:
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
Let x = amount of pure antifreeze required
Pure antifreeze is 100% = 1x
.10(5)+x = .40(x+5)
.5+x = .4x+2
.6x = 1.5
x = 2.5 gallons of pure antifreeze are needed
:
John

Answer by ikleyn(52784)   (Show Source): You can put this solution on YOUR website!
.
Also see the lesson
    - Word problems on mixtures for antifreeze solutions
in this site.


Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
How many quarts of pure antifreeze must be added to 5 quarts
of a 10% antifreeze solution to obtain a 40% antifreeze solution?

Here's another way to think of it:

The 5 quarts of 10% antifreeze contains (5)(0.10) = 0.5 quart of pure 
antifreeze, (and the rest of the 5 quarts is 4.5 quarts of water, 
which we aren't concerned with).

We are adding X quarts of pure antifreeze to the 0.5 quarts of pure 
antifreeze (and water).  So after pouring them together, 
there will be X+0.5 quarts of pure antifreeze in the mixture.  And 
that will make 5+X quarts of liquid.

The equation is 



            

Multiply both sides by (5+X)

            

            

Multiply through by 10 to clear the decimals.  

            

            

            

            

            

Edwin


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