SOLUTION: larry mitchell invested part of his $34,000 advance at 5% annual simple interest and the rest at 7% annual simple interest. the yearly total from both was $2,300. Find the amount a

Algebra.Com
Question 1034320: larry mitchell invested part of his $34,000 advance at 5% annual simple interest and the rest at 7% annual simple interest. the yearly total from both was $2,300. Find the amount at each rate.
Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
Call the amount invested at 5%, x.
Then the amount invested at 7% would be 34000-x.
The set up then looks like this...
.05x + .07(34000-x) = 2300
Now solve for x...
.05x + 2380 - .07x = 2300
-.02x = - 80
x = $4000 invested at 5% which means
34000-4000 = $30,000 invested at 7%

RELATED QUESTIONS

Larry Mitchell invested part of his $30,000 advance at 5% annual simple interest and the... (answered by greenestamps)
Larry Mitchell invested part of his $21,000 advance at 8% annual simple interest and the... (answered by addingup)
larry mitchell invested part of his 14,000 advance at 7% annual simple interest and the... (answered by Boreal)
Larry Mitchell invested part of his $27,000 advance at 7% annual simple interest and the... (answered by solver91311)
Larry Mitchell invested part of his $ 35,000 advance at 7% annual simple... (answered by addingup)
Larry Mitchell invested part of his $29,000 advance at 8% annual simple interest and the... (answered by addingup)
Larry Mitchell invested part of his $ 32,000 advance at 4% annual simple interest and the (answered by ikleyn)
Larry Mitchell invested part of his $16,000 advance at 5% annual simple interest... (answered by ewatrrr)
Larry Mitchell invested part of his $22,000 advance at 5% annual simple interest and the... (answered by addingup)