SOLUTION: "Seven apples and one orange cost ninety eight cents. Two apples and three oranges cost sixty six cents. Find the cost if one Apple and one orange" please help with this, I'm lost!

Question 1033857: "Seven apples and one orange cost ninety eight cents. Two apples and three oranges cost sixty six cents. Find the cost if one Apple and one orange" please help with this, I'm lost!
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
No worries...let's call the costs of apples and oranges, x and y.
Then we write
7x + y = 98 and
2x + 3y = 66
Now let's multiply the top equation by 3 and subtract it from the bottom one...we get
2x + 3y = 66
-(21x + 3y = 294)
-----------------
-19x = -228
Now divide by -19 and get
x = 12 (apples are 12 cents each)
Now plug that in to the first equation and get
7(12) + y = 98
84 + y = 98
y = 14 cents
So an apple and an orange would cost 12 + 14 = 26 cents...how's that?
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