SOLUTION: The currrent, I0 (measured in amperes), decreases to I amperes after t seconds according to the formula I = I0e−0.51t. When 25 amperes decreases to 2.5 amperes, the equation
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Question 1026192: The currrent, I0 (measured in amperes), decreases to I amperes after t seconds according to the formula I = I0e−0.51t. When 25 amperes decreases to 2.5 amperes, the equation is 2.5 = 25e−0.51t. Rounded to the nearest tenth of a second, how long, t, does it take for the current to decrease from 25 amps to 2.5 amps?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
When and I = 2.5, we have .
==>
==> 0.51t = ln10 ==> seconds.
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