SOLUTION: Daniel has $1200 in the bank. He is earning 3.5% compound interest each month. How much money will he have in the bank in one year?
Algebra.Com
Question 1022468: Daniel has $1200 in the bank. He is earning 3.5% compound interest each month. How much money will he have in the bank in one year?
Found 2 solutions by Cromlix, Alan3354:
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
100 + 3.5
= 103.5%
= 103.5/100 = 1.035
$1200 x 1.035^12
= $1813.28 after a year.
Hope this helps :-)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Daniel has $1200 in the bank. He is earning 3.5% compound interest each month. How much money will he have in the bank in one year?
-------------
If it's 3.5% per month (not likely, that's loan shark interest) the other tutor's answer is good.
---
If it's 3.5% per year compounded monthly that's 3.5%/12 per month.
Use (1 + 0.035/12)^12 as the multiplier.
RELATED QUESTIONS
Aldo is going to a bank to start a savings account for his college fund. The bank will... (answered by mananth)
if someone has 360 dollars in his savings account in the bank he earns 3% interest each... (answered by stanbon,richwmiller)
Richard received a bank statement of $1260 for two years simple interest earning. If the... (answered by josgarithmetic,MathTherapy)
A bank pays 3% compound interest per year. Jeremy invests $2 000. How much money will he... (answered by Cromlix)
Mr Jake deposited an amount of 10 000 in a bank that pays 4% annual interest compound... (answered by jorel1380)
Mr. Bill saved money the following way. On the first day, he put $1 in the bank. On the (answered by solver91311)
Each week, Ben deposits the same amount of money into his bank account. Today, he has 42$ (answered by stanbon,MathTherapy)
Conner has 25,000 in his bank account. Every month he spends $ 1,500. He does not add... (answered by math-vortex)
Carla has $1000.00 in her bank account. Each year, she receives 50% interest on the total (answered by stanbon)