SOLUTION: Word Problem:
A movie theater charges $7.50 admissions for and adult and $5 for a child. If 700 tickets are sold on a particular day and the total revenue received is $4500, how
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Question 1014371: Word Problem:
A movie theater charges $7.50 admissions for and adult and $5 for a child. If 700 tickets are sold on a particular day and the total revenue received is $4500, how many tickets of each type are sold?
I need to make an equation and then solve it.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
x is the number of adults.
y is the number of children.
7.5x is the total amount of revenue based on x number of adults.
5y is the total amount of revenue based on y number of children.
total number of tickets sold is 700.
equation for that is x + y = 700
total revenue is 4500.
equation for that is 7.5x + 5y = 4500
these two equations need to be solved simultensouly becsuse the same value of x and y applies to both.
equations are:
x + y = 700
7.5x + 5y = 4500
solve for y in the first equation to get y = 700 - x
replace y with 700 - x in the second equation to get 7.5x + 5y = 4500 becomes 7.5x + 5 * (700 - x) = 4500
solve for x in the second equation.
start with 7.5x + 5 * (700 - x) = 4500
simplify to get 7.5x + 5*700 - 5x = 4500
combine like terms and simplify to get 2.5x + 3500 = 4500
subtract 3500 from both sides of the equation to get 2.5x = 4500 - 3500
simplify to get 2.5x = 1000
divide both sides of the equation by 2.5 to get x = 1000 / 2.5
solve to get x = 400
x is the number of adult tickets.
since x + y = 700, then y = 300
you have 400 adult tickets and 300 children tickets.
400 + 300 = 700 so that's ok.
7.5 * 400 + 5 * 300 = 3000 + 1500 = 4500 so that's ok as well.
solution is 400 adult and 300 children tickets were sold.
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