SOLUTION: a wallet contains only $5 bills and $10 bills. The number of $10 bills is four more than the number of $5 bills. the value of the money is $160. how many of each type of bill are i

Question 1012184: a wallet contains only $5 bills and $10 bills. The number of $10 bills is four more than the number of $5 bills. the value of the money is $160. how many of each type of bill are in the wallet?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
F=number of $5 bills; T=number of $10 bills=F+4
.
$5F+$10T=$160
$5F+$10(F+4)=$160
$5F+$10F+$40=$160
$15F=$120
F=8
ANSWER 1: There are 8 five dollar bills.
.
T=F+4=8+4=12
ANSWER 2: There are 12 ten dollar bills.
.
CHECK:
$5F+$10T=$160
$5(8)+$10(12)=$160
$40+$120=$160
$160=$160

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