SOLUTION: if 40 people at a restaurant spend a total of $600 and half of the 40 people spend one half of what the 20 other people spend, what is the least amount of money a person spent

Question 1004694: if 40 people at a restaurant spend a total of $600 and half of the 40 people spend one half of what the 20 other people spend, what is the least amount of money a person spent
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
20x+20(x-1/2x)=600
20x+20x-10x= 600
30x= 600
x= 20
20 people spent $20 each and the other 20 spent 20*1/2= $10 each.
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Proof:
20*20= 400
20*10= 200
_ _ _ -----
Total...600 We have the correct answer
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