SOLUTION: one positive number exceeds twice another number by 3 and the product of the two numbers is 44. Find the smaller number.
Algebra.Com
Question 997650: one positive number exceeds twice another number by 3 and the product of the two numbers is 44. Find the smaller number.
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x = smaller number
y = larger number
y = 2x + 3
xy = 44
Substitute.
x(2x + 3) = 44
2x^2 + 3x - 44 = 0
(2x + 11)(x - 4) = 0
The numbers are positive, so smaller = 4 and larger = 11.
RELATED QUESTIONS
One positive number exceeds another by 4, and their product is 96. Find the... (answered by CubeyThePenguin)
one number exceeds another number by 2 and the product of the two numbers is 143. Find... (answered by algebrapro18)
One number exceeds by 8, and the sum of the smaller and twice is 40. Find the product of... (answered by greenestamps)
One number exceeds another by 15 find the smaller number of the sum of the two numbers is (answered by ikleyn)
1. One number is greater by 6 than twice another number, but 3 times the smaller number... (answered by ewatrrr)
one number exceeds another number by 6. Write these two numbers in terms of x. When twice (answered by macston)
The product of two numbers is 44. One number is 3 more than twice the other number. Find (answered by JulietG,mananth)
The sum of two numbers is 80 and the greatest number exceeds twice the smaller by 11.... (answered by rfadrogane)
the sum of two numbers is 90 and the greater number exceeds twice the smaller by 15. find (answered by Alan3354)