SOLUTION: 2 tables and 3 chairs together cost $2140, but 3 tables and 2 chairs together cost $2760. find the individual cost of the table and the chair.

Question 987435: 2 tables and 3 chairs together cost $2140, but 3 tables and 2 chairs together cost $2760. find the individual cost of the table and the chair.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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T=cost of table; C=cost of chair
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2T+3C=$2140 Multiply by 3.
6T+9C=$6420
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3T+2C=$2760 Multiply by 2.
6T+4C=$5520 Subtract this from second equation above.
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5C=$900
C=$180
ANSWER 1:One chair costs $180.
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2T+3C=$2140
2T+3($180)=$2140
2T+$540=$2140
2T=$1600
T=$800
ANSWER 2: One table costs $800.
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CHECK:
(Use second equation)
3T+2C=$2760
3($800)+2($180)=$2760
$2400+$360=$2760
$2760=$2760

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