SOLUTION: It's Math 243 (Intro Probabil & Stats).
The question: The heights of women aged 20 to 29 follow approximately the distribution N(64.3, 2.7) (in inches). Men the same age have he
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Question 985377: It's Math 243 (Intro Probabil & Stats).
The question: The heights of women aged 20 to 29 follow approximately the distribution N(64.3, 2.7) (in inches). Men the same age have heights distributed as N(69.9, 3.1) (in inches). What percent of young women are taller than the mean height of young men?
Found 2 solutions by Boreal, rothauserc:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
A woman at the men's average height is (69.9-64.3)/2.7 sd from the mean or a z-score of +2.074.
;-
This becomes a problem of the probability of having a z-score greater than +2.074.
It is 0.0190, or 1.9%.
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
P ( X > 69.9 ) = 1 - P ( X < 69.9 ), where P is probability
calculate z-score for P ( X < 69.9 )
z-score = ( 69.9 - 64.3 ) / 2.7 = 2.074074074 approx 2.07
P ( X < 69.9 ) = 0.9808, therefore
P ( X > 69.9 ) = 1 - 0.9808 = 0.0192 approx 0.02
There is 2% of young women taller than the mean height ( 69.9 ) of young men
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