SOLUTION: two positive whole number differ by three the sum of the squares is 117 find the larger of the two numbers
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Question 981830: two positive whole number differ by three the sum of the squares is 117 find the larger of the two numbers
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x and x-3 are the numbers.
x^2+(x-3)^2=117
x^2+x^2-6x+9=117
2x^2-6x-108=0
x^2-3x-54=0
(x+6)(x-9)=0
positive number is 9
other is 6.
The sum of squares is 81+36=117.
The larger is 9.
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