SOLUTION: if a projectile is fired straight upward from the ground with an initial speed of 64 feet per second, then its height in feet after seconds is given by the function h(t)=-16t^2 + 6

Question 962753: if a projectile is fired straight upward from the ground with an initial speed of 64 feet per second, then its height in feet after seconds is given by the function h(t)=-16t^2 + 64t. find the maximum height of the projectile.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
if a projectile is fired straight upward from the ground with an initial speed of 64 feet per second, then its height in feet after seconds is given by the function h(t)=-16t^2 + 64t. find the maximum height of the projectile.
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h(t)=-16t^2 + 64t
complete the square
h(t)=-16(t^2 -4t+4)+64
h(t)=-16(t-2)^2+64
This is an equation of a parabola that opens upward with vertex at (2,64)
maximum height of the projectile=64 ft (2 sec after it is fired)
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