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put this solution on YOUR website!Question:
A rectangle has a perimeter of 78centimeters. The length of the rectangle is 11 centimeters longer than triple the width. Find the dimensions of the rectangle.
Answer:
Given:
perimeter = 78centimeters
suppose width = x centimeters
tripple the width = 3x
11 centimeter longer than tripple the width = 3x + 11
That is length = (3x + 11 ) centimeters
Perimeter is given by the formula,
Perimeter = 2(length + width)
That is:
78 = 2( 3x + 11 + x)
==> 78 = 2(4x +11)
==> 78 = 2* 4x + 2*11
==> 78 = 8x + 22
Subtract 22 from both sides....
==> 78 - 22 = 8x + 22 - 22
==> 56 = 8x
Divide both sides by 8
==>
==> 7 = x
That is width = 7 centimeters.
Then length = 3x + 11 = 3*7 + 11 = 21 + 11 = 32 centimeter.
That is dimensions of the rectangle is;
length = 32 cm and
width = 7 cm
To check your answer, plugg these values in the given formula of perimeter of the rectangle, P = 2(length+width) then you will get the answer 78 centimeters.
Hope you found the explanation useful.
Regards.
Praseena.
