SOLUTION: A cashier has a total of 30 bills, made up of ones, fives, and twenties. The number of twenties is 9 more than the number of ones. The total value of the money is $351. How many of

Question 841912: A cashier has a total of 30 bills, made up of ones, fives, and twenties. The number of twenties is 9 more than the number of ones. The total value of the money is $351. How many of each denomination of bills are there?
Must write 3 equations from the word problem and solve the system of equations using either the substitution or elimination method showing all work.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
A cashier has a total of 30 bills, made up of ones, fives, and twenties.
o+f+t=30,
The number of twenties is 9 more than the number of ones.
t=9+o,
The total value of the money is $351.
o+5f+20t=351
so we have
o+f+t=30,
t=9+o,
o+5f+20t=351
f = 9, o = 6, t = 15
check
5*9+6+15*20=351
45+6+300=351
ok

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