SOLUTION: Ok, just need these set up... 1. Maria has $1.05 in dimes and nickels. She has 6 more nickels than dimes. How many nickels does Maria have? 2. What is the equation for the

Question 8013: Ok, just need these set up...
1. Maria has $1.05 in dimes and nickels. She has 6 more nickels than dimes. How many nickels does Maria have?
2. What is the equation for the sum of three times a number and five is fourteen?
Answer by glabow(165) (Show Source): You can put this solution on YOUR website!
You just need these "set up" and not solved, right?
You choose variables for the number of dimes and nickels. Let's use d and n.
So since a d is worth 10 cents and an n is worth 5 cents,
10d + 5n = 105
Also, n is 6 more than d. That is, if we knew how many n there were, we could find how many d there were by subtracting 6. So,
n - 6 = d
You put this value for d in the first equation and get
10n - 60 + 5n = 105
Solve that and you know how many nickels there were.
Then subtract 6 and you know how many dimes there were.
I say "were" because by now Maria has spent them!
Your second question just reads like algebra. Let n be the number.
So, three times the number and then five more is fourteen.
3x + 5 = 14
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