SOLUTION: A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what ti

Question 67531: A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
A bus(A SAY) leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later
DISTANCE TRAVELED BY A IN 1 HR=44*1=44 MILES
a second bus(B SAY) leaves the same station, traveling east at a rate of 48 mi/h.
HENCE INITIAL DISTANCE OF SEPARATION BETWEEN A & B = 44 MILES
At what time will the two buses be 274 mi apart?
FINAL DISTANCE OF SEPARATION BETWEEN A AND B =274 MILES
HENCE DIFFERENCE IN DISTANCE =274-44=230 MILES
A AND B ARE TRAVELING IN OPPOSITE DIRECTIONS...SO
RELATIVE SPEED = 44+48=92 MPH
TIME = 230/92=2.5 HRS.
HENCE THE 2 BUSES WILL BE 274 MILES APART AT 1=00 PM +1 HR + 2.5 HRS =4.5 PM
4=30 PM

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