SOLUTION: thanks so much for helping me, guys!...i am almost finished with this unit, but unfortunately i am stumped again. imagine you are serving a volleyball underhanded. suppose you h

Question 65416: thanks so much for helping me, guys!...i am almost finished with this unit, but unfortunately i am stumped again. imagine you are serving a volleyball underhanded. suppose you hit the ball when it is 3 feet above the ground, and it leaves your hand with an initial upward velocity of 20 feet per second.
general formula for height: H=-1/2*gt^+vt+h where g is the acceleration due to gravity, and on the earth, equals 32ft/sec^. v is the initial upward velocity of the object and h is the initial height above the ground.
the question is: what is the maximum height that the volleyball will reach and how many seconds will it take to reach this height?
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Imagine you are serving a volleyball underhanded. suppose you hit the ball when it is 3 feet above the ground, and it leaves your hand with an initial upward velocity of 20 feet per second.
general formula for height: H=-1/2*gt^+vt+h where g is the acceleration due to gravity, and on the earth, equals 32ft/sec^. v is the initial upward velocity of the object and h is the initial height above the ground.
the question is: what is the maximum height that the volleyball will reach and how many seconds will it take to reach this height?
h=3, v=20, and g=32
The formula for height:

The maximum height is the H value of the vertex.
The formula for finding the t value of the vertex is: for a quadratic equation in this form:
a=-16, b=20, and c=3

The maximum height H, will happen when t=.625 s.

The Maximum height is: 9.25 ft or 9 ft 3 in
Happy Calculating!!!
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