SOLUTION: At time t = 0 a slingshot fires an egg straight up from a window of a tall building. The height of the egg above ground as a function of time is given by
y = -4.9t2 + 21t + 5
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y = -4.9t2 + 21t + 5
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Question 633364: At time t = 0 a slingshot fires an egg straight up from a window of a tall building. The height of the egg above ground as a function of time is given by
y = -4.9t2 + 21t + 56, where y is in meters and t is in seconds. a. How high up is the window? b. How high is the egg after 3 s? c. After launching the egg, how long does the shooter have to wait to see the egg go by the window on the way down? d. At what times is the egg 65 m above ground? (Solve with the quadratic formula; then check your work using the trace feature of a graphing calculator.) e. When does the egg impact the ground? Answer by richwmiller(9143) (Show Source):
You can put this solution on YOUR website! a)The window is 56 meters above the ground.
b) 74.9 meters
c)t=4.28571
d)t=3.80271 t=0.483007
e)t=6.14541
